Question

U.S. Foreign-Born Workers In 2004, there were 20 million foreign-born workers in the United States. The circle graph below shows the occupations of those workers.
Occupations of Foreign-Born Workers in the United States

Please see attachment for diagram.

If one foreign-born worker is selected at random, determine the empirical probability the person’s occupation is in
a) the service industries.
b) construction-related industries.
c) management or is a professional.

Answer 1

and it is not 23%, 13% and 26%

Answer 2

Service industry :
23% of workers, so p(e) = 0.23

Construction related industry :
13% => p(e) = 0.13

Managment :
26% => p(e) = 0.26

Answer 3

my teacher said that, that was wrong.

Answer 4

he said "The percents of the given population. Look at the number of people surveyed."

Answer 5

But 23% of 200m, or any population is still 23% probability. Did he said anything aside ?

Answer 6

you need to fing the % of the given population.

Answer 7

that is what he said and that was all.

Answer 8

and its 20m not 200m

Answer 9

I know its confusing. im still trying to wrap my brain around it and i can't get anything to come out.

Answer 10

Ah, I missed the word empirical : it is then \[p = \frac{s}{n}\] with p : probability, s : succeful trial, N: number of trial. If we try one time (one worker), then the empirical probability is 1. (1sucess over one trial) for every question. But it is very strange.

Answer 11

ok i get it so far.

Answer 12

p(occupation is in service industry) = 23/100

P(construction related industry) = 13/100

P(management or professional) = 13/50

Answer 13

i did that and the teacher said that was wrong.

Answer 14

see total no of people is 20,000,000
people in service industry is 23% = 23% of 20,000,000 = 4,600,000

so P(occupation is in service ind) = 4,600,000/20,000,000 = 23/100 !!!!

Answer 15

This is regular probability, whereas the teacher asked for empirical probability, wich obey the formula I given.