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write the quation of a hyperbola with the center at the orgin having verticies (0,-7) and (0,7) and the foci at (0,-9) and (0,-9)
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thats not an equation of a hyperbola...
hold on... gimme a minute
it is y^2/49 -x^2/32 =1
how do you figure that out?
a = distance of vertex from center. so a=7 c = distance of focus from center =9 b^2 = c^2-a^2 = 81-49=32 since the vertices are (0,-7) and (0,7), it is symmetrical across the x axis so it has the equation y^2/a^2 - x^2/b^2 =1
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