Question

1/4x^2-3x+3=0 solve using the quadratic formula

Answer 1

quadratic formula is -b+or- the square root of b^2-4ac all over 2a. a in this case is 1/4, b is -3, c is 3.

Answer 2

\[-(-3)\pm \sqrt{(-3)^{2}-4(1/4)(3)}\div2(1/4)\]

Answer 3

why is b -3

Answer 4

which is positive 3 since the negative of a negative is a positive plus or minus the square root of negative 3 squared, which is positive 9, since a negative times a negaitve is a positive minus 4 times 1/4, which is 1, times 3 is 3. so inside the radical you have

Answer 5

cant you multiply everything by 4 to get rid of the fraction

Answer 6

multiply by 4 to give yourself a break with all these fractions

Answer 7

9-3 which is 6 and that is now 3 plus or minus the sqare root of 6 all over 2 times 1/4 which is 1/2

Answer 8

ok and when i multiply by 4 i get x^2-12x+12=0

Answer 9

\[x^2-12x+12=0\] then easy to use formula. easier still to complete the square:
\[(x-6)^2=-12+36=24\]
\[x-6=\pm\sqrt{24}\]
\[x=6\pm\sqrt{24}\]

Answer 10

Yes, it's so much easier to complete the square. That's what satellite taught me in precalc, and now my classmates all use quad formula, and I solve the answer much faster.

Answer 11

no muss no fuss. and you can even write s
\[x=6\pm 2\sqrt{6}\] if you like

Answer 12

ok i got another problem x^2+7x+2=0

Answer 13

if i complete the square i get (x+49/4)^2