Question

how to solve 2x-√15-4x=0

Answer 1

if it is
\[2x-\sqrt{15-4x}=0\]
\[2x=\sqrt{15-4x}\]

Answer 2

then do what after that

Answer 3

then square both sides to get
\[4x^2=15-4x\]
\[4x^2+4x-15=0\]
\[(2x-3)(2x+5)=0\] and so
\[2x-3=0\]
\[2x=3\]
\[x=\frac{3}{2}\]

Answer 4

or
\[2x+5=0\]
\[2x=-5\]
\[x=-\frac{5}{2}\]

Answer 5

but you have to check your answers because we squared as the second step. you need to plug in both of these numbers for x and see if they both work

Answer 6

you can check for yourself but i think both work. is it clear how to check?

Answer 7

hold on I'm checking it right now

Answer 8

k

Answer 9

Yeah it works! thanks you're awesome!

Answer 10

yw!