The perimeter of a rectangle is 56 inches. The length is 4 more than 3 times the width. What are the dimensions of the rectangle? Write the system of equations that would be used to solve this problem.

Write the system of equations that would be used to solve this problem. 2L +2W=56 L= 3W+4 Solve the system of equations in problem #3. ANSWER: Solve by substitution: 2(3W+4) +2W = 56 6W+8 +2W = 56 8W = 56-8 8W=48 W=6 From L=3W+4 L=3(6)+4 =18+4 =22 What is the length of one side of the rectangle? 6 inches 12 inches 22 inches 44 inches ANSWER: This question is ambiguous because there are four sides. If the questioner means the width, then it’s 6 inches if the length, then it’s 22 inches.

It asks for dimensions it's not ambiguous Your answer is correct the rectangle is 6 by 22

yes :D