The perimeter of a rectangle is 56 inches. The length is 4 more than 3 times the width. What are the dimensions of the rectangle?

Write the system of equations that would be used to solve this problem.

Question

The perimeter of a rectangle is 56 inches. The length is 4 more than 3 times the width. What are the dimensions of the rectangle?

Write the system of equations that would be used to solve this problem.

anonymous · Answer

Write the system of equations that would be used to solve this problem.
2L +2W=56
L= 3W+4
Solve the system of equations in problem #3. 
ANSWER:
Solve by substitution:
2(3W+4) +2W = 56
6W+8 +2W = 56
8W = 56-8
8W=48
W=6
From 
L=3W+4
L=3(6)+4
=18+4
=22
What is the length of one side of the rectangle? 

6 inches
12 inches
22 inches
44 inches
ANSWER:
This question is ambiguous because there are four sides. If the questioner means the width, then it’s 6 inches if the length, then it’s 22 inches.

anonymous · Answer

It asks for dimensions it's not ambiguous 
Your answer is correct the rectangle is 6 by 22

anonymous · Answer

yes :D