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OpenStudy (anonymous):
what is the slope of a line that is PERPENDICULAR to the line represented by the equation 3x+4y=12? 4/3 3/4 -3/4 -4/3
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OpenStudy (anonymous):
a
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
its 4/3
OpenStudy (tad1):
The slope of a perpendicular line is always the negative reciprocal of the original line's slope. y = 3x + 5. the slope of the perpendicular line would be -1/3. For y =-(2/5)x -9. te slope of the perpendicular line would be 5/2. When you multiply the two slopes together the product will b negative 1, which is why they are called negative reciprocals.
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