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Mathematics 19 Online
OpenStudy (anonymous):

Factor -2bk2 + 6bk - 2b.

OpenStudy (anonymous):

Pull out a -2b from every term. After that, there's not much you can do.

OpenStudy (anonymous):

first simplify, you will get: -4bk+6bk-2b obviously, they all have something in common: 2 and b is in each part. So: 2b(-2k+3k-1) now we can add -2kand 3k: 2b(k-1)-final answer

OpenStudy (anonymous):

I took the -2bk2 to be \[-2bk^{2}\] @youngbpd, is that correct?

OpenStudy (anonymous):

is it k^2???

OpenStudy (anonymous):

I think so.

OpenStudy (anonymous):

if so you are absolutely right.

OpenStudy (anonymous):

Either way, between the two of us he has the correct answer ^_^

OpenStudy (anonymous):

I dont mind you to be right)))

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