Mathematics
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OpenStudy (anonymous):
Given that
f(x) =-2xh(x)
h(5) = -1 and h'(5)=-3
find f'(5)
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OpenStudy (bahrom7893):
f(x) = -2x * h(x)
f'(x) = -2x * h'(x) + (-2) * h(x)
OpenStudy (bahrom7893):
f'(5) = -2*5-h'(5) + (-2) * h(5)
OpenStudy (bahrom7893):
f'(5) = -10-(-3)+(-2) *(-1)
OpenStudy (bahrom7893):
f'(5) = -10+3+2=-5
OpenStudy (anonymous):
sorry mate that isn't one of the options
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OpenStudy (anonymous):
not even close :-)
OpenStudy (bahrom7893):
I see my mistake..
OpenStudy (anonymous):
sweet, I am more concerned with how to understand this one
OpenStudy (bahrom7893):
-2*5*h'(5) + (-2) * h(5)
f'(5) = -10*(-3)+(-2) *(-1)
f'(5) = 30 + 2 = 32
OpenStudy (bahrom7893):
is that better? haha
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OpenStudy (anonymous):
f(x) = -2xh(x)
h(5) = -1
h'(5) = -3
f'(x) = -2x[h'(x)] + -2(h(x))
f'(5) = -2(5)(h'(5)) + -2(h(5))
= -10(-3) + -2(-1)
= 30 + 2 = 32
OpenStudy (anonymous):
I agree.
OpenStudy (bahrom7893):
I don't know where that - came from haha..
OpenStudy (anonymous):
yes, much better. Im going through it to see where I went wrong _ thanks!!
OpenStudy (anonymous):
did you use the chain rule?
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OpenStudy (anonymous):
pls explain if possible would really help
OpenStudy (anonymous):
why did you plug in the h's like you did?
OpenStudy (bahrom7893):
okay here we go:
first use the chain rule:
f'(x) = -2x * h'(x) + (-2) * h(x)
OpenStudy (anonymous):
Actually that's the product rule. I was wrong about the chain rule earlier.
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
But what you have written is otherwise correct.
OpenStudy (bahrom7893):
*oh sorry it is.. i never remember the names..haha
OpenStudy (anonymous):
can I write the f(x) like this f(x) = (-2x)((h(x)) ?
OpenStudy (anonymous):
Certainly.
OpenStudy (bahrom7893):
yea..
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OpenStudy (bahrom7893):
then use the product rule..
OpenStudy (anonymous):
perfect! now I see the product rule instead of me futzing around with the chain rule.
Thanks a ton!!!
OpenStudy (bahrom7893):
sorry =P
OpenStudy (anonymous):
I was doing it loooong before I put the question up - def my fault