Question

Can someone help please
In 1993, the life expectancy of males in a certain country was 70.8 years. In 1997, it was 73.3 years. Let E represent the life expectancy in year t and let t represent the number of years since 1993.
The linear function E(t) that fits the data is

E(t) = -- + --
round to nearest tenth

Use the function to predict the life expectancy of males in 2007.

E(14) = ---
round to the nearest tenth

Answer 1

hmm...
So I will let years be the x - axis or the variable, and the life expectancy will be y..
x = 3, y = 70.8
x = 7, y = 73.3

Answer 2

Now write the equation using those two points:
y-y1 = M(x-x1), where M is the slope.

Answer 3

M = (y-y1)/(x-x1) = (73.3-70.8)/(7-3) = 2.5/4

Answer 4

M = 0.625
so:
y-73.3 = 0.625(x-7)
y = 0.625x - 0.625*7 + 73.3

Answer 5

y = 0.625x + 68.95

Answer 6

or you could just say:
E(t) = 0.625t + 68.95, just replace all Ys with E and Xs with t

Answer 7

Now to find E(14):
E(14) = 0.625*14 + 68.95 = 77.7

Answer 8

so in 2007, the expectancy should be about 77.7 years

Answer 9

thanks bahrom7893
so the linear function for E(t) = 0.625t + 68.95 is that correct

Answer 10

yes

Answer 11

ok than you u get a medal

Answer 12

can i become your fan

Answer 13

sure lol