Question

show that dy/dx= x+2/ 2squareroot 1+x
u=x v=(1+x)-1/2
u`=1 v`=-1/2(1+X)^-3/2

Answer 1

u ( v') + v ( u')

Answer 2

its u ( v') - v ( u') but I cant get the answer it give 3x+2/ 2squareroot(1+x)

Answer 3

oh wait

Answer 4

its v (u') - u (v')/ v^2

Answer 5

yeah lol

Answer 6

but if you use
u=x v=(1+x)-1/2
u`=1 v`=-1/2(1+X)^-3/2

I cant get it to give i3x+2/ 2squareroot(1+x)

Answer 7

let me try this out

Answer 8

can u post the original equation ?

Answer 9

the original equation is y=x square root 1+X
then you have to show that dy/dy= 3x+2/2 suare root 1+X

Answer 10

oh k lets try this 1

Answer 11

i got the answer right

Answer 12

could u please show your solution becuase I think my working out is wrong

Answer 13

1st of all u = x
v = sqrt 1+x
u' = 1
v' = 1/2sqrt 1+x

formula u (v') + v( u')
x ( 1/2 sqrt 1+x) + sqrt 1+x ( 1)
x/ 2 sqrt 1+x + sqrt 1+x
take lcm
x + 2 (sqrt( 1+x )) (sqrt 1+x )/ 2 sqrt 1+x
x + 2 ( 1+x) / 2 sqrt 1+x
x+ 2 +2x / 2sqrt 1+x
3x + 2 / 2 sqrt 1+x

Answer 14

Thankyou :)

Answer 15

N p :) where r u from ?

Answer 16

Rochdale But I go Oldham Sixth Form wbu?

Answer 17

Pakistan :)

Answer 18

oh lol Im in England :)

Answer 19

yeah i know
:P

Answer 20

how come you usedu (v') + v( u') when the formlua is u (v') - v( u') over \[2^{(v)}\]

Answer 21

I mean \[\over v)^{2}\]

Answer 22

the formula u ( v') + v ( u') is used when in the equation u and v are multiplied
v ( u') - u ( v') / V^2 is used when u and v are divided in the equation.

Answer 23

in this equation x is multiplied with sqrt x+1

Answer 24

so we used 1st formula !

Answer 25

ohright I get it now :) thanks lol where about do u live in pakistan?

Answer 26

Karachi :) and u muslim ?

Answer 27

yeah :)

Answer 28

Masha' Allah :D

Answer 29

Thankyou :)

Answer 30

how did you get? x/ 2 sqrt 1+x + sqrt 1+x and what do you mean by lcm?

Answer 31

you need to multiply the other term with the denominator to get the single denominator.