hydrogen peroxide can decompose to water and oxygen by the following reaction

2H2O2 (l) ------ 2H2O(l) + O2(g) enthalpy=-196kj
calculate the value of q when 5.00g of h20(l) decomposes at constant pressure.

Question

hydrogen peroxide can decompose to water and oxygen by the following reaction

2H2O2 (l) ------ 2H2O(l) + O2(g) enthalpy=-196kj
calculate the value of q when 5.00g of h20(l) decomposes at constant pressure.

anonymous · Answer

1 mole of H2O2=34.0148 g
5.00g of H2O2=5/34.0148=0.146995 moles
decomposition of 2moles produce -196kj
therefore q produced by 0.146995 moles of H2O2=(-196/2)*0.146995=-14.40551Kj
i think this is the way , i hve not been through this calculation for a long period~9-10years
sorry if there is a mistake...........

anonymous · Answer

the answer is correct...thanx for the explanation