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solve the equation 3^n-12=1/81
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go nikita!
3^n = 12 + 1/81 = (12*81 +1)/81. \[\log_{3}3^{n} = \log_{3}((12*81 +1)/81)\] \[n = \log_{3}(81*12 + 1) - 4 \] but \[\log_{3}(81*12 + 1) \] not integer. (
my options are 9, 8, -8 and 16
did you want n-12 to be the exponent?
yes
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ok put parathesis around you exponents so we know k?
okay sorry
so n-12 = -4
its cool
gj nakita if you solve n-12=-4 for n you will get your answer
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n=-4+12=8
really?)
lol
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