Question

given that :
f(3)=1 f '(3)=-5
g(3)=-8 g '(3)=9

calculate (f*g)'(3) and (f/g)'(3)

Answer 1

\[(fg)'=f'g+g'f \] so fill in the numbers

Answer 2

\[(fg)'(3)=-5\times -8+1\times 9\]

Answer 3

i get -31

Answer 4

49 for the first one, which is correct.

Answer 5

right because i can't do artithmetic. 49 is right

Answer 6

\[(\frac{f}{g})'=\frac{gf'-fg'}{g^2}\]

Answer 7

got both, thanks :]

Answer 8

so we get
\[\frac{-8\times-5-9\times 1}{(-8)^2}\]

Answer 9

i will leave arithmetic to you
yw