Question

-3c^2-6c=45

Answer 1

divide by -3 throughout . Then it is simple quadratic equation

Answer 2

if we divide by -3 through out we get
\[c ^{2}+2c=-15\]
\[c ^{2}+2c+15=0\]
solve it ahead u should try on ur own now

Answer 3

i do't seem to understand

Answer 4

srry don't

Answer 5

okay lets do it a another way
\[-3x ^{2}-6x=45\]
\[-3(x^{2}+2x)=45\]
\[x ^{2}+2x=45/-3\]
45/-3=-15
\[x ^{2}+2x+15=0\]

Answer 6

-3x\[^{2}\]-6c-45=0
we want to get rid of the negative so u multiply all of it by negative so it becomes:
3x\[^{2}\]+6c+45=0
u factor it so it becomes :
(3c-9)(c+5)

Answer 7

not possible if we expand this (3c-9)(c+5)=\[3c ^{2}+6c-45\]

Answer 8

yes i think im wrong... u have to simplify and do the steps that u did ...