Question

quadratic equation....need to show the steps
x² - 2x – 13 = 0 and x² + 12x – 64 = 0

Answer 1

First one:
first find the discriminant:
D = 4 - 4 * (-13) = 56
x1 = [ (-(-2) - sqrt(56) ] / 2

Answer 2

x^2 + (b+c)x + (bc) = 0 is the format to use.

b+c = -2

bc = -13 ; solve for b and c

Answer 3

x2 = [ (-(-2) + sqrt(56) ] / 2

Answer 4

it aint gonna play nice :) so complete the square maybe?

Answer 5

Do the same steps for the next equation using the quadratics formula:
ax^2 + bx + c = 0
D = b^2 - 4ac
x1 = (-b - sqrt(D)) / (2a)
x2 = (-b + sqrt(D)) / (2a)