Question

Write the slope-intercept equation for the line that passes through (-9, 9) and is perpendicular to -9x – 2y = 10

Answer 1

-9/2

Answer 2

If the line is perpendicular then it has a negative reciprocal slope. So the slope would be 2/9 (solve the above equation you get y=(-9/2)x-5)
Then you have a point. Use point slope form.
\[y-y_0=m(x-x_0) \rightarrow y-9=(2/9)(x-(-9))\]
Then solve. You should get:
y=(2/9)x+11

Answer 3

I got it mal...

Answer 4

slope for the given line -9x-2y=10 when placed in slope intercept form will be
-2y=9x+10 becomes y=-(9/2)x-5 The coefficient of x is the slope and it is -(9/2)

Any line that is perpendicular to that line of slope -(9/2) will be the negative reciprocal. that means the slope for the perpendicular line will be a (2/9) note that it is positive. and is the reciprocal.

Now this line is said to go through P(-9,9). With the slope now known, and the point given we can write the equation for the perpendicular line in the slope intercept form.

y-9=m(x--9) that is actually y-9=m(x +9) substituting the value of the slope
y-9=(2/9)x+(2/9)9
y=2x/9 + 2 +9 or
y=(2/9)x + 11
just as malevolence 19 worked it out.

Answer 5

Good :D