Question

2 3+a 2
-- - --- + --------- =
a+3 2a+6 a²+6a+9a²

Answer 1

first you need to make a common denominator to add all these fractions.
a²+6a+9a²=(a+3)^2
2a+6=2(a+3)
so we can see that the least common denominator will be 2* (a+3)^2

Now you have to expand all
there will be
(2*2*(a+3) -(3+a)(a+3) +4)/(2(a+3)^2
4a+12-a^2-6a-9+4/(2(a+3)^2
(-a^2-2a+7)/(2(a+3)^2)

Answer 2

are you sure this is correct. I do not have that answer

Answer 3

no it looks ugly, probably I did some mistake, I am too tired. I really should go to bed

Answer 4

hope that the idea behind it is clear

Answer 5

-2 3a+7
-- - --- ---------
2(a+3)(a+3) 2a²+12a+18

-1 9a+25
---------- ---------
2(a²+6a+9) 2(a+3)²


these are my choice,which is the correct one?

Answer 6

have a goodnight