Question

using the method to solve quadratic equations that came from India how would i solve this:
x^-2x-13=0
i understand the first few steps:
x^-2x=13
4x^-8x=52
4x^-8x+4=52+4
4x^-8x+4=56
how do i solve for x now?

Answer 1

subtract 56 from the left, then use the quadratic formula: -b plus or minus the sqrt of the quantity b squared - 2ac end quantity all divided by 2a.

Answer 2

I get confussed on how to sqrt numbers...not good at algebra

Answer 3

use a calculator. or if its a simple square like 144, then just use that number

Answer 4

I'll try using a calculator and see if I can figure it out

Answer 5

You should end up with two numbers too. One when you add the sqrt and one when you subtract it. DON'T FORGET TO USE BOTH OF THEM!!! (unless one of them doesn't fit the story).