using the method to solve quadratic equations that came from India how would i solve this:
x^-2x-13=0
i understand the first few steps:
x^-2x=13
4x^-8x=52
4x^-8x+4=52+4
4x^-8x+4=56
how do i solve for x now?

Question

using the method to solve quadratic equations that came from India how would i solve this:
                             x^-2x-13=0
 i understand the first few steps:
 x^-2x=13
 4x^-8x=52
 4x^-8x+4=52+4
 4x^-8x+4=56
 how do i solve for x now?

anonymous · Answer

subtract 56 from the left, then use the quadratic formula: -b plus or minus the sqrt of the quantity b squared - 2ac end quantity all divided by 2a.

anonymous · Answer

I get confussed on how to sqrt numbers...not good at algebra

anonymous · Answer

use a calculator. or if its a simple square like 144, then just use that number

anonymous · Answer

I'll try using a calculator and see if I can figure it out

anonymous · Answer

You should end up with two numbers too. One when you add the sqrt and one when you subtract it. DON'T FORGET TO USE BOTH OF THEM!!! (unless one of them doesn't fit the story).