what is the area of a regular, NON-right angled triangle with sides 240, 180, and 140 m?
why is it regular?
Use Heron's formula:A=\[\sqrt{p(p-a)(p-b)(p-c)}\]
where p=Perimeter/2 and a,b,c are the lengths if the sides
Area of a triangle is \[1/2ab \sin C\] Where a b and c are sides and A B and C are the angles opposite to the sides.
so that is the angle inbetween the two sides, right?
Heron's formula works always if u have the 3 lengths....why r u mixing it with sin?
trigonometry. never heard of heron's formula :P but thanks guys :)
@angela triangles and trigonometry go together like butter and bread! hahaha
yea i know....but ..am i blind or there's no angle given...
You use the cosine rule: \[c ^{2} = a ^{2} + b ^{2} - 2ab \cos C\] The reason i used this is that these fomulae are the most commonly used ones. Heron's would be easier but is lesser known and is not usually given on formulae sheets
@ angela: but you can find that out using the cos rule. CosA= (b^2 + c^2 - a^2)/2bc. I am doing a past paper, so i was asking according to the instructions given.
I didn't know that...In Albania we use it a looooooooooot...I thought you knew it :)
ohh. cool B)
im gonna learn herons, it looks very useful.
:)lol
@angela: wait. are you in school/college, what is the "p" in the formula?
finished hs and I've written above that p=P/2( half of perimeter )
read the article i sent cause you'll get it
sry, sry, didn't see that there :P
:)it's k
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