Question

solve the equation x(square) -4x +1 =0

Answer 1

use quadratic formula, you'll get:
\[x=2+/-2\sqrt{3}\]

Answer 2

http://en.wikipedia.org/wiki/Quadratic_equation

Answer 3

\[x^2 - 4x + 1 = 0\]
\[x= 2 +/ - 2\sqrt{3}\]

Answer 4

need detailed solution

Answer 5

\[ax ^{2} + bx + c = 0\]
To solve, you need to use the quadratic equation:
\[x = (-b \pm \sqrt{b ^{2}-4ac}) / 2a\]"2a" divides both the "-b" and the square root.

In your problem you have a = 1, b = -4, and c = 1
\[x = (-(-4)\pm \sqrt{(-4)^{2}-4(1)(1)})/2(1)\]
Simplify to get...\[x = (4/2) \pm (\sqrt{12}/2) = 2 \pm (2\sqrt{3}/2) = 2 \pm \sqrt{3}\]