Question

log _x 9 = -2
x is the base

i get the question.. its just when you have x^-2 = 9... it becomes 1/x^2 = 9... then HOW does it become x^2 = 1/9 ? what is done there?

Answer 1

cross multiply: 9* x^2 = 1
divide both sides by 9:
x^2 = 1/9

Answer 2

oh i see thank you!!

Answer 3

\[1 /x ^{2} = 9\]

Answer 4

yw