Question

Solve: 18/(s+v) = 18/(s-v) -9

Answer 1

which one is unknown: s or v?

Answer 2

both of them

Answer 3

the ans seems to be 4v=s^2 - v^2 , but not sure how

Answer 4

you need two equation to uniquely solve for two unknowns...
possible answers: s = 0, v = 4,
or s = 1, v = -2+/- sqrt(5).
and so on and on...

Answer 5

so now: which one is your unknown?

Answer 6

Yes, this is the first one, confused with this one, the ans seems to be 4v=s^2 - v^2 , but not sure how

Answer 7

the ans of the first equation

Answer 8

let me show you guys how to do this: first you HAVE TO assume one variable is known. you CANNOT have two vars there in ONE eq and hope to solve it.
let's say s is known, then you can easily convert this equation into a quadratic eq by multiplying both sides by (s-v)(s+v), then solve for v, and the answer is:
v = +/-sqrt(s^2+4)-2.
you can also do the same for s expressed with v.

Answer 9

if you want integer solution.. then that is it: s = 0, and v= 4.

Answer 10

otherwise, what you get is a Hyperbola

Answer 11

\[\frac{18}{s+v}*(s-v)(s+v)=\frac{18}{s-v}*(s-v)(s+v)-9*(s+v)(s-v)\]
\[18(s-v)=18(s+v)-9(s^2-v^2)\]
\[18s-18v=18s+18v-9s^2+9v^2\]
\[18s-18s-18v-18v=-9s^2+9v^2\]
\[-36v=-9s^2+9v^2\]
\[\frac{-36v}{9}=\frac{-9s^2}{9}+\frac{9v^2}{9}\]
\[-4v=-s^2+v^2\]
\[(-1)*-4v=(-1)(-s^2+v^2)\]
\[4v=s^2+v^2\]

Answer 12

but apple is right we need to know what to solve for

Answer 13

it just say solve

Answer 14

i did not say your answer is wrong, but i hope you also understand that rewriting an equation is not the same as solving an eq.... you have to move your unknowns to one side, and knowns to the other.. that is called solving an eq.
even if it says solve for 4v, you still have v on the other side....

Answer 15

yes i know lol

Answer 16

i'm trying to say it would be nice for it to say solve for something instead of solve

Answer 17

right. good luck.

Answer 18

you too