find the measure of the angle ABC. given: A(3,0,0) B(0,1,0) C(1,2,3)
Perimeter?
no have to find the angle :)
hmm....let me see a formula..I've 4gotten it :(
cosθ=(x1x2+y1y2+z1z2)/|u||v|
thats what i used but it could be the wrong formula
(a1a2a3+b1b2b3) the angle between 2 lines is cosA =------------------------------------ sqr(a1^2+b1^2+c1^2)*sqr(a2^2+b2^2+c2^2) k1k2+1 Or cosA=--------------------------- sqr(k1^2+1*sqr(k2^2+1)
too messy
yes i used the same formula i dont know why my answer came out wrong
is the angle between vector AB and vector AC correct
i thought u might have to find the eq of the lines and then use the coefficients or slopes...
AB(-3,1,0) and AC(-2,2,3)
i dont think so. But i could be wrong
Or i can be wrong...
lol
omg this is killing me:)
I don't have the idea how to do it...:S:S ...Sorry..:(:( Survive till some1 else helps u though :P:P
lol ill try
^_^ lol
this is what i got
and have you opened it?
yep just a quick question. when you find the vector AB shouldnt it be the vector b-a?
you know i was never sure about that lol you are probably right i never had a class on this, but i have looked at it
AB and BA have different direction so they are different vectors right?
thats correct
i know we want to find angle B so I know I'm suppose to use CB/BC and AB/BA but i'm not sure what to use maybe I think i;m suppose to use AB and BC
yes i was thinking the same the thing is when i use AB and AC my answer is wrong lol
AB=<0-3,1-0,0-0> BC=<1-0,2-1,3-0>
AB dot BC=-3(1)+1(1)+0(3)=-3+1=-2 mag{AB}=sqrt{9+1}=sqrt{10} mag{BC}=sqrt{1+1+9}=sqrt{11}
\[\cos^{-1}(\frac{-2}{\sqrt{110}})\]
what do you think of that?
the answer is \[\approx 79.01 degrees\]
so your working out before was closer the answer
omg the first one i had was right
lol sorry
so its BC and BA
so yes i labeled them wrong that is so weird how i didn't bother with the directions and i wounded up doing the right way with wrong labels
lol
thanks heaps :)
thanks for teaching me alittle bit about vectors
Congratz guys :)
by the way and you called me a guy earlier i am not lol
using BC and BA make sense since we listed the angle we looking for first that angle being B
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