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OpenStudy (anonymous):
what is the standard form of the line y=-x+3/5? a) -5x-5y=3 b) 5x-5y=3 c) -5x+5y=3 d) 5x+5y=3
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OpenStudy (angela210793):
D i guess
OpenStudy (radar):
The "general form" is ax + by +c = 0 For this case it would be: -x-y+3/5=0 or -5x-5y+3=0 or 5x+5y -3=0 or modified slightly 5x+5y=3
OpenStudy (anonymous):
D is the correct answer because. y=-x+3/5. Multiply everything by 5 to get rid of the fractions. 5y=-5x+3, then add 5x to each side. 5y+5x=3
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