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Mathematics 16 Online
OpenStudy (anonymous):

What is the solution set of the absolute value sentence |6x + 8| > -4? A. {4/3, -4} B. {x|x > 4 or x < -4/5} C. No Solution D. {x|-11 < x < -7} E. All Real Numbers

OpenStudy (anonymous):

ok.

OpenStudy (anonymous):

Even better...here's the trick. An absolute value is always positive...and your asking when will that number be greater than *negative* 4...

OpenStudy (anonymous):

Can a positive number ever be less than -4?

OpenStudy (anonymous):

Of course, when I say positive, I also am including 0...although 0 is neither positive nor negative.

OpenStudy (angela210793):

how come i got ]-2/3;-2[

OpenStudy (anonymous):

? hmmm

OpenStudy (anonymous):

Can a positive (or zero) ever be less than -4?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@angela - if you do work on this problem it will lead you weird. Just look at what the question is asking.

OpenStudy (anonymous):

@lisa - how can a positive number be smaller than a negative number?

OpenStudy (anonymous):

expression on the left is absolute value. expression on the right is less than zero. do not try to solve using algebra

OpenStudy (anonymous):

OH SRY!!

OpenStudy (anonymous):

:) s'ok...since as @satellite said, the expression on the right is an absolute value, it is *always* going to be either 0 or positive...and therefore *always* > -4. So what is the answer?

OpenStudy (anonymous):

x>-2, x<-2/3

OpenStudy (anonymous):

im still kinda confused

OpenStudy (anonymous):

FIrst, you understand that 0>-4. Now, whatever 6x+8 equals, when you take it's absolute value, it is going to be positive. So for all real numbers, x, that you choose,\[\left| 6x+8 \right|\ge0>-4\]

OpenStudy (anonymous):

So no matter what we choose for x, the inequality holds true. Better?

OpenStudy (anonymous):

@jeremy - don't try using algebraic methods...it won't work.

OpenStudy (anonymous):

Okay so basically how you have to do it is through the following steps. First do 6x+8>-4, subtract 8 from each side and you get 6x>-12. Now divide each side by six and you get x>-2. Now for the second solution (which all inequalities have), multiply (6x+8) times -1. Then you get -6x-8>-4. Add eight to each side and you get -6x>4. Then divide each side by -6 and you switch the inequality sign and get x<-2/3. So the two solutions are x>-2, and x<-2/3

OpenStudy (anonymous):

That's incorrect jeremy.

OpenStudy (anonymous):

@jeremy - look at @satellite's post

OpenStudy (anonymous):

so it would be E

OpenStudy (anonymous):

Very good @lisa. Do you understand why?

OpenStudy (anonymous):

Oh you're right. It would obviously be all real numbers because anything in the absolute value bar is positive. Therefore every number because positive numbers are obviously greater than -4

OpenStudy (anonymous):

I POSTED ANOTHER QUESTION LIKE IT... AM I RIGHT?

OpenStudy (anonymous):

You now have a third "tool" to use to solve these. The two I gave you earlier on translating the inequalities...and now, An absolute value greater than a negative numebr is true "for all real numbers." Math is all about learning tools that help you solve the problem.

OpenStudy (anonymous):

Let me look at it and see. :)

OpenStudy (angela210793):

thnx guys :)

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