how do you solve log base5 125?

Question

anonymous · Answer

Well, first I'd look to see if 125 is a power of 5

angela210793 · Answer

$$\log_{5} 125=3$$

angela210793 · Answer

cause 5^3=125

anonymous · Answer

what aout log$$\log _{2}64 ?$$

anonymous · Answer

Is 64 a power of 2?

anonymous · Answer

yes

anonymous · Answer

Which power of 2?

anonymous · Answer

768

anonymous · Answer

Angela, let her figure it out pls..

angela210793 · Answer

$$\log_{a} b=c $$ so that a^c=b

anonymous · Answer

$$2^{768}=64?$$

anonymous · Answer

6?

angela210793 · Answer

Wht did I do wrong? why did u deleted it? o.O

anonymous · Answer

im really not good with this

angela210793 · Answer

delete*

anonymous · Answer

$$2^6 = 64 \implies log_2(64) = 6$$

anonymous · Answer

All you have to do is figure out how many 2's you have to multiply to get 64. That number is the log(base 2) of 64.

anonymous · Answer

i didnt delete it and ok thankyou @polpak & @angela210793

angela210793 · Answer

$$\log_{a} b$$=c cause a^c=b a in this case is 2 and B is 64

anonymous · Answer

here : log x , base = y :::: x ^ y = base  then its log5,125 = 3 ^^

angela210793 · Answer

I know u didn't delete it....
and uw :)

anonymous · Answer

i think "what is logarithm?" would be a better questiont ... ^^

angela210793 · Answer

yes Korcan agree :)

angela210793 · Answer

anonymous · Answer

and now angela help in my questions
?

angela210793 · Answer

still integrals?

anonymous · Answer

Pleeeaseeeee :) pleeeeaseeee

anonymous · Answer

I find that this is typically sufficient explanation..
$$log_ba = k \iff b^k = a$$

angela210793 · Answer

@Korcanlet me see if i can solve them
@Polpak she didn't understand it that's y i ave her the link...

anonymous · Answer