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solve for x in log6x + log 3=1
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Recall that the sum of logs is the product of their arguments: \[log(a) + log(b) = log(a\cdot b)\] So in this case, how can we rewrite log6x + log 3?
is the base 10?
hello polpak!
If the base isn't specified it's usually assumed to be 10.
you are still green i see.
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yes i have made that assumption before. then it turned out i was wrong
Yes, but it is fortunately not a function of my health ;)
;)
i think these problems are posted, then the person who posts goes for lunch and comes back expecting an answer!
Well, since the user abandoned the question anyway I suppose we'll never know ;)
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Often they are right in that assumption (unfortunately).
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