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slope -4;y-intercept (0,-3/5)
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y = -4x -3/5
To do this, do y-y1 = m(x-x1)
What this means is: y = just regular old y y1 = the y value from your point (-3/5) x = just regular x x1 = 0
so, y-(3/5) = -4(x-0)
Sorry... y-(NEGATIVE 3/5) = -4(x-0)
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you get: y+ 3/5 = -4x + 0 Move the 3/5 to the right and you have: y = -4x - 3/5 Make sense? ^_^
yes and thanks guys
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