Question

|n|>n
Solve inequality

Answer 1

is tht it?

Answer 2

N is any negative answer.
The reason is because a positive is ALWAYS greater than a negative number, and an absolute always leads to a positive.

Answer 3

So, if you took, say... -15 as n,
you'd have:
|-15| > -15
15 > -15

And so on.

Answer 4

I'm no idea , I coppy exactly from tex book

Answer 5

@California: Your answer's ready for you. :P

Answer 6

|n|<n
the key is : {n|-9n->0
|n|<n I no idea this answer

Answer 7

So it's this, you said?

{n|-9n->0

Answer 8

When you have an inequation, you can use the method of critical points to determine solution sets. Here, \[|n|>n\]so we start by looking for partition points via,\[|n|=n \iff \sqrt{n^2}=n\]where I've used one of the definitions for absolute value here. Hence,\[\sqrt{n^2}=n \rightarrow n=\pm n\]which is only true for n=0. So n=0 partitions the number line. We pick a point in each interval and test in the original inequality. If it tests true for that point, all n in that interval will be part of the solution set.

1) Pick n=1. Then\[|1|>1\] --> not true. So n > 0 is not part of the solution.

2) Pick n =-1. Then \[|-1|>-1\] --> true. So n < 0 is part of the solution.

n = 0 is not part of the solution, which you can check in the inequality.

Hence the solution set is all real n such that n < 0.

Answer 9

Loki agrees with me. Woo.

Answer 10

Hehe.

Answer 11

uber {n|-9n->0 is not answer
I said this answer for another similar problem , just a sample

Answer 12

{n|-9n->0 is answer for |n| <n not |n|>n

Answer 13

There is no solution for |n|<n.

Answer 14

No offense prashant, but it may be time to throw the book at the publisher. Like literally.

Answer 15

Lol.

Answer 16

Erm... I mean california.mathematics Not prashant.

Answer 17

|n|>n;
case(1) when n>0 then |n|=n as n is positive;
-> |n|>n
-> n>n
-> no number is greater than itself;
case (2) when n<=0 then |n| = -n as n is negative;
-> |n|>n
-> -n>n
-> 2n<0
-> n<0 means n is from -infinite to 0 iliminating 0 as our case is n<=0 so this answer also not violate our case(n<=0);
hence answer is n<0 where n is real no.
note:-> to solve inequality with modulus, take cases and solve them within each case;
and be sure that your outcome doesn't violate your case assumed....

Answer 18

let me send your guy text book for answer key
number 28) and 29)

Answer 19

Ah!

Answer 20

It says |n| > OR EQUAL to n!
The only answer would be 0.

By the way, the answers you're showing don't match up to the section you posted. :P Double check your page numbers/chapters.

Answer 21

yes because my key board no equal side

Answer 22

u sai the key 29) is was wrong?

Answer 23

Ya, I'm sorry. The key is wrong. It doesn't make sense. The number line they drew is correct. The actual numbers they put is not.

Answer 24

what answer 28)?

Answer 25

I'm confose I need repost

Answer 26

No prob. Gimme medal.