Question

4X^3+9X^2+2=0

Answer 1

Did you make a mistake on this question or the last? Should the last term be 2x in your question?

Answer 2

yes it should be

Answer 3

Going by your last question, you just factor.\[4x^3+9x^2+2x=x(4x^2+9x+2)=x(4x+1)(x+2)=0\]so\[x=0, x=-\frac{1}{4}, x=-2\]

Answer 4

what happened to the 9?

Answer 5

1.x + 2.4x = 9x

Answer 6

say whaaaa

Answer 7

where did the 2.4 come from??

Answer 8

4x in (4x+1) and 2 in (x+2)

Answer 9

You can factor the quadratic by grouping.\[4x^2+9x+2=4x^2+8x+x+2=4x(x+2)+1(x+2)=(4x+1)(x+2)\]

Answer 10

thanks that clears up a lot of confusion! :)

Answer 11

np :)

Answer 12

Happy to help