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find the inverse of f(x) = sqrt(4-e^2x)
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multiplicative inverse?
1/sqrt(4-e^2x)
thats not right
solve it for x=... let f(x) = y then: y^2=4-e^2x 2x=ln|4-y^2| x=1/2 ln|4-y^2| now write inverse function as: f=1/2 ln|4-x^2|
is it good?
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i dont understand the answer
inverse function is 1/2 on natural ln of absolute value (...): \[f=1/2 \ln|4-x ^{2}|\]
after y^2=4-e^2x I am LOST!
how do you finish solving for x
e^2x=4-y^2 take ln both sides: 2x=ln|4-y^2| x=... because it's inverse - just change places for x& y
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ok i understand now
so what will be the domain of the inverse function
\[4-x^{2}>0\] because ln
\[x^{2}<4\] -2<x<2
-2 doesnt work
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that's why (-2) & 2 are not included. it simple more & less (not equal)
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