Question

derivative of y=x^lnx?

Answer 1

Hint:
You know that lnx = 1/x, right?
Now use product rule.

Answer 2

[2y(ln x)] / x
= [y * 2(ln x)] / x
= [y(ln(x^2))] / x

Answer 3

Remember that a(ln b) = ln b^a

Answer 4

I mean... you know that derivative of lnx = 1/x

Answer 5

dont i use logarithmic differentiation?

Answer 6

take log on both sides
lny = (lnx)^2
dy/ydx = 2lnx/x
dy/dx = 2ylnx / x

Answer 7

use implicit differentiation after that

Answer 8

get it?

Answer 9

yes

Answer 10

thanks

Answer 11

no thank you lol