Question

48j^5k^2 ÷ (-3j^3k)

Answer 1

i would just multiply by the reciprocal

Answer 2

i'm confused

Answer 3

Rewrite as\[48j^{5}k^{2}/-3j^{3}k\]Divide the 48 by the 3 to cancel it on the bottom

Then cancel exponents of the like variables...remember when dividing, you subtract the bottom exponent from the top exponent.

Understand?

Answer 4

\[\frac{48j^5k^2}{-3j^3k}\] and do what mtbender said. divide the numbers, subtract the exponents.

Answer 5

of course visualize the exponent of k in the denominator as 1 so you have
\[-16j^{5-3}k^{2-1}\]