Question

9^x-1=27

Answer 1

\[2(x-1)=3\]
is a start

Answer 2

9^x = 28
x ln 9 = ln 28
x = ln 28/ln 9

Answer 3

9^x-1=27
9^x=28
log9^x=log28
xlog9=log28
x=log28/log9
x=1.516551628

Answer 4

27 = 3^3
9 = 3^2

so

(3^2)^x-1 = 3^3
3^2x-2 =3^3

since base is same, powers have to be equal
so 2x - 2 = 3
2x = 3+2
x = 5/2

Answer 5

To three significant digits, x = 1.52. If the original problem is supposed to be
9^(x - 1) = 27, then Harkirat is correct.

Answer 6

Those parentheses make a big difference.

Answer 7

true!! without them it is difficult to decide which way to go
i went one way and you the other.........

Answer 8

Well, at least all bases are covered:^)

Answer 9

i am willing to bet based on the other problems that it is
\[9^{x-1}=27\]