Question

simplify the following fraction (please show work!).... (x/2x+3) - (4/5x-1)

Answer 1

is it

x 4
(--- + 3 ) - (---- - 1) ?????
2x 5x

Answer 2

i have no idea what you just typed

Answer 3

is this your question as printed in the book ???

Answer 4

\[(x \div2x +3)-(4\div5x -1)\]

Answer 5

ok ill ask again because it is still not clear

is it x divide by (2x+3) minus 4 divided by (5x-1) ??

Answer 6

yes

Answer 7

ok, then i know the right question...

Answer 8

ok can you answer it plz

Answer 9

x(5x-1) - 4(2x+3)
= ------------------ (taking LCD)
(2x+3) (5x-1)

5x^2 - x - 8x -12
= --------------------
10x^2 - 2x + 15x - 3

5x^2 - 9x - 12
= ---------------
10x^2 + 13x - 3

Answer 10

i cant understand this can you explain step by step

Answer 11

since both terms r fractions, we have to take their LCD
when denominators are algebraic terms which have no common factor visible, we take LCD as their product.

Now we divide the LCD by the denominator of each fraction and multiply the numerator by the remainder....

(2x+3)(5x-1)
------------ leaves (5x-1) so we multiply the numerator x by (5x-1)
(2x+3)


(2x+3)(5x-1)
------------ leaves (2x+3) so we multiply the numerator 4 by (2x +3)
(5x-1)

then we resolve the brackets.....

is it clear now????

Answer 12

can you give me a final answer using the equation button

Answer 13

\[5x ^{2} - 9x - 12\]
-------------------\[10x ^{2} + 13x -3\]

Answer 14

thanks i get what your saying now would you mind helping me with\[(2\div \cos \theta)+(4\div1-\sin \theta)\]

Answer 15

let me see...... give a minute or two

Answer 16

sorry, not able to find a proper way to do it, pls put it out as a new question for others....

Answer 17

ok could you answer a diffrent question