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OpenStudy (anonymous):
solve... cos^2 x+2cos x=0
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OpenStudy (anonymous):
cosx{cos x + 2) = 0
cos x = 0 or cos x = -2
there is angle with cos = -2
x = 90 degrees or 20 degrees
OpenStudy (anonymous):
sorry - no angle with cos = -2
x = 90 or 270 degrees
OpenStudy (anonymous):
\[\cos^2 x + 2\cos x=0\]
OpenStudy (anonymous):
does this clear things up
OpenStudy (anonymous):
He already worked it out above for you. The question to you: does that clear things up?
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OpenStudy (anonymous):
not really sorry
OpenStudy (anonymous):
You have to say what you don't understand; because he did it step for step.
OpenStudy (anonymous):
i dont understand what he wrote can you use the equation button
OpenStudy (anonymous):
i dont understand what he wrote can you use the equation button
OpenStudy (anonymous):
The equation button helps if there is an exponent or a base number. It is just writing an equation.
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OpenStudy (anonymous):
how about we start from the begining
OpenStudy (anonymous):
All he did was 'pull' the cos x out. For example, suppose it was
4+2
That is the same thing as
2(2+1)
That is what he did to your cos x.
OpenStudy (anonymous):
oh ok now i get it
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