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Mathematics 17 Online
OpenStudy (anonymous):

find derivates using definition.. f(x)= 1/x+2

OpenStudy (anonymous):

Awesome.... These are fun. Ready to work on this together?

OpenStudy (anonymous):

yes..ready..

OpenStudy (anonymous):

Sweetness! First, how would we go about solving this? Like what equation/idea are we going to use?

OpenStudy (anonymous):

If you need a hint, I can give you one.

OpenStudy (anonymous):

equation that i know, lim f(x+h)-f(x)/h h approaches 0

OpenStudy (anonymous):

perfect! That's the difference quotient. And do you know how we use it?

OpenStudy (anonymous):

Also, I just want to double check: Your original equation is one over x, plus 2 right? Not 1 over (x+2)?

OpenStudy (anonymous):

i dont exactly how to use it please teach me

OpenStudy (anonymous):

yes..1 over (x+2)

OpenStudy (anonymous):

Okie dokie.

OpenStudy (anonymous):

the f(x+h) part means rewrite the original question, BUT, instead of X write (x+h) each time you see it. So how would you equation, 1/(x+2) appear if you replace the x with (x+h) ?

OpenStudy (anonymous):

*your equation, I mean.

OpenStudy (anonymous):

actually i 've try..i got the answer is -(1 over (x+2)square..is it same as u?

OpenStudy (anonymous):

Unfortunately no.

OpenStudy (anonymous):

You literally just replace x with (x+h). No math needed yet.

OpenStudy (anonymous):

1/(x+2) just replace the x with x+h and what does it say?

OpenStudy (anonymous):

Ah oh well. I've gotta go assist other folks then.

OpenStudy (anonymous):

oh..so what ur answer?

OpenStudy (anonymous):

1/(x+h+2) You literally just replace x with x+h :P

OpenStudy (anonymous):

ok2..tq..i got it

OpenStudy (anonymous):

how about this question \[f(x)= 1 \over \sqrt{x-1}\]

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