Find the derivative of the function. y = (5x - 4)^4(8x^2 - 5)^-3
Wanna work on this one together?
yes, please :)
Alright! You know about chain rule?
I do, but I still mess it up when trying to solve problems.
Lol, it's cool. I'm only in my second week of cal, so I can't judge.
Alright, you can tell it's going to be a fraction due to the negative power, right?
yes
Alright! What we'll want to do is to use quotient rule. Can you tell me what the quotient rule is?
(What sucks is that it's difficult to explain while typing out the equations. These types of questions are looongggg and look much better on paper)
finding the derivative of a function that is the quotient of another function
Yup. And do you know what exactly it is? Like the equation itself?
no
Okie dokie.
is it d/dx
It isn't. But before I explain that, could you rewrite the original equation in fraction form?
Here's your original equation to help: y = (5x - 4)^4(8x^2 - 5)^-3
(5x-4)^4 / (8x-5)^3
Perfect!
Ok, so here we go: We will assume the numerator is g(x) and the denominator is h(x)
then i got this 4(5x-4)^3 (10x-1) / (5-8x)^4
but i'm confused myself how i ended up with (10x-1)
The difference quotient says that the derivative of two functions in the form of: g(x) /h(x) is equal to this beast: http://upload.wikimedia.org/math/3/8/5/3856f28d4b93877f760d4dbd301176cd.png
Well, we'll see if that's right as we go through this. ^_^ Does that equation I linked to make sense?
somewhat
Alright. If you have pen and paper (hopefully you do, because we're going to use a lot of it), you should write down this stuff:
can you tell me what g(x) is equal to?
Remember: "Ok, so here we go: We will assume the numerator is g(x) and the denominator is h(x)"
(5x-4)^4= g(x)
perfect! Be sure to write that down.
and what is h(x)?
(8x-5)^3= h(x)
awesome! Now looking back at the link I posted, we're missing two things (not including f'(x), which is the answer we're looking for obviously). What two things are we missing?
Here's the link again: http://upload.wikimedia.org/math/3/8/5/3856f28d4b93877f760d4dbd301176cd.png remember, we know g(x) and h(x)
Oh nooooesss... did you run away? :P
no
are we missing the primes
Perfect! And the primes means the derivatives. So here's where the 'fun' begins!
You wanna do g'(x) first or h'(x)?
h'(x)?
okie dokie.
h(x) was defined as (8x^2 - 5)^3 does this sound good so far? (I might have made typoes, so double check please)
yes
Awesome. So let's do this. Wanna take a guess at the first step we must do?
factor? which i'm horrible at :(
Nope, we don't have to do that at all ^_^
So that must be a relief :P
Alright, remember power rule?
oh yea
kinda
Well, quick review: could you power rule this for me: x^4
BTW, I need to depart in about 10 minutes. :(
x^4-1= x^3
close. We need to do something more.
oh no... :'(
hint: x^2 will turn into 2x^1
ah..
So what does x^4 turn into?
4x^3
perfect!
Ok I'll remind you of how chain rule works now. :D
ok
Here's what our original problem was: (8x^2 - 5)^3
With chain rule, you first do powerrule while making believe the stuff inside the parenthesis is your X. However, because the stuff inside the parentheses is NOT X, you have to also derive that stuff next. I will show an example.
"differentiate (2x)^3" So... we can agree that (2x) isn't really x So here's what we do: 1. Make believe it IS x, and do power rule: 3(2x)^2
does this one make sense?
(there's one more step after this, just to warn you. We're not done yet)
kinda
Well, to double check, I'll let you do one: (5x+4)^3 Could you do the power rule to it like I did?
3(5x)^5
Kinda close.
3(5x)^3
5(3x)^3
(5x+4)^3 a. drop the three up front 3(5x+4)^3 b. lower the 3 exponent by 1 (it's ALWAYS minus 1 no matter what) 3(5x+4)^2
Did that up there make sense?
yes it did
awesome. So I just want to be 100% sure that you've got this: Do step one of the chain rule to this: (8x-6)^9
9(8x-6)^8
heck ya! :D
:D
Here's step two of the power rule: Multiply it by the derivative of the stuff inside the parentheses. So... let's go ahead and continue the previous example. 9(8x-6)^8 What is the 'stuff inside the parentheses'?
Gotta go real soon, so please answer quickly lol
(72x-54)^8
We can't do that yet unfortunately. Just lemme know what the stuff inside the parentheses are.
(8x-6)
perfect! So step two of the chain rule wants us to multiply step 1, which was 9(8x-6)^8 with the derivative of 'the stuff inside the parentheses'. So, what is the derivative of the stuff inside the parentheses?
Just the derivative; we aren't going to multiply anything yet.
I don't understand that , sorry
no problemo!
What if we changed it from (8x-6) to just 8x-6 Does that make it less scary?
Like, "derive 8x-6"?
if it still doesn't make sense, just lemme know.
ah.... so confused
It's ok. Alright, do you remember that any number without a variable turns into 0 when you derive it?
They should have explained that in cal class.
So do you remember that one? You've gotta tell me or I won't know what to explain. :P
I don't remember my professor can't speak english for pellet
Lol. Just write this down: The derivative of a constant is zero.
ok
Join our real-time social learning platform and learn together with your friends!