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show that ∫tanx from 0 to π/4= 1/2In2
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i know that ∫tanx = ∫sinx/cosx = -In(cosx)
then from there you get -In cos( π/4)
omg my i accidently pressed back button damn it
ohh that sucks lol
maybe u can tell me where i went wrong in mine?
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\[-\ln(\frac{\sqrt{2}}{2})=-\ln(\frac{\sqrt{2}}{\sqrt{4}})=-\ln(\sqrt{\frac{2}{4}})=-\ln(\frac{2}{4})^\frac{1}{2}\] =\[-\frac{1}{2}\ln(\frac{1}{2})=\frac{-1}{2}(\ln1-\ln2)=\frac{-1}{2}(0-\ln2)=\frac{1}{2}\ln2\]
you remember that cos(pi/4) is sqrt{2}/2 right?
lol for some reason i made Sqrt(2)xsqrt(2) =4 silly mistake lol
lol
i all makes sense now thank you:)
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ok im your fan i see you so much lol
lol thank you
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