Question

Solve:
3y2 - 48 = 0

Answer 1

Alright use the process of elimination by eliminating 48 from the equation.
3y2-48=0
+48 +48
Then you get 3y2=48

now to get rid of the three divide both sides

3y2=48
divide by 3

y2=16

divide 16 by two and you have 8 which is your answer

Answer 2

Is that what you needed?

Answer 3

3y2 - 48 = 0 hi if this is like this 3y^2 - 48 = 0
3y^2 - 48 = 0
3y^2 =48
y^2 =48/3=16
y=sqrt 16
y=-4 ans
y=-4 ans

Answer 4

is it 8 or -4 ?

Answer 5

depends how the 3y2 is meant

is it 3y2 or is it\[3y ^{2}\]

Answer 6

\[3y ^{2}-48=0\]\[3y ^{2}=48\]\[y ^{2}=48/3=16\]\[y= sqrt{16}=pm 4\]

Answer 7

y=+/- 4

Answer 8

\[y=\sqrt{16}=\pm 4\] There it is the equation editor was sick!