Question

hey guys i need to complete the square for this problem: If 3x^2 – 2x + 7 = 0 Can someone help??:)

Answer 1

sure but it is a pain

Answer 2

ok thank you:))

Answer 3

\[3x^2-2x=-7\]
\[x^2-\frac{2}{3}x=-\frac{7}{3}\]

Answer 4

that is to get the leading coefficient 1, otherwise you cannot complete the square.

Answer 5

then take half of
\[-\frac{2}{3}\] square it and add it to the other side

Answer 6

\[(x-\frac{1}{3})^2=-\frac{7}{3}+\frac{1}{9}\]

Answer 7

\[(x-\frac{1}{3})2=-\frac{20}{9}\]

Answer 8

now take the square root. your answer is complex because you have a negative number on the right

Answer 9

thank you so much!!! that is all i needed!!

Answer 10

youre a great teacher:D

Answer 11

satellite stop being so glamorous

Answer 12

\[x-\frac{1}{3}=\pm\frac{20}{3}i\]

Answer 13

satellite let me teach you splitting the middle please its easy

Answer 14

hello my myininaya

Answer 15

split the what???

Answer 16

i factor by setting = 0 and solving. that is the only way i know how.

Answer 17

oh forgot to complete the problem.
\[x=\frac{1}{3}\pm\frac{\sqrt{20}}{3}i\]

Answer 18

haha thank you, i'm studying for my cpt and this was confusing the heck out of me.