Question

3-4(z+1)=3z-(2+z)
Solve for Z

Answer 1

Here's how you could solve this. First, expand the brackets
\[3 - 4 z - 4 = 3 z -2 -z\]
Which you simplify to:
\[ -4 z -1 = 2z -2 \]
Now add \(4 z\) to both sides of the equation:
\[ -1 = 6 z -2 \]
And add 2 to both sides:
\[ 1 = 6 z \]
Divide by \( 6 \)
\[ 1/6 = z \]
So \( z = 1/6 \). Insert this into the original equation to check.

Answer 2

3-4(z+1)=3z-(2+z)
3-4z+4=3z-2-z
z=1/6
check; 3-4(1/6+1)=3(1/6)-(2+1/6)
-5/3=-5/3