how do I sketch y = 1 + ln(x-2)?

Question

anonymous · Answer

Just like any other graph. Find values for x

anonymous · Answer

how about in term of shifts:

y = x^2 + 5, shift y = x^2 up by 5

anonymous · Answer

that was just an example.

I was asking what I need to do to the graph of y = ln x to get the graph I want.

anonymous · Answer

ln x is a number in the same way x^2 is a number.

anonymous · Answer

Not quite, the domain is restricted to positive reals.

anonymous · Answer

I am not saying they are like or similar numbers; but he or she is unsure about ln x: I am merely saying it is a number.

anonymous · Answer

I am saying that for sketching purposes x must be >2.

anonymous · Answer

ok, x must be greater than 2, what about the 1, do I shift the graph upward by 1?

anonymous · Answer

just choose any numbers applicable and get an idea of the graph and draw it. There is no need to shift, unless that is some specific instructions your teacher gave you.

anonymous · Answer

Choose values of x higher than 2.

anonymous · Answer

If you set x = 3, y = 1 + ln 1 = 1

anonymous · Answer

The normal graph of ln is asymptotic to  negative y....