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Mathematics 19 Online
OpenStudy (anonymous):

what is the derivative of f(x) = ln(x^2 +10)?

OpenStudy (amistre64):

do you recall the derivative of ln(x) ?

OpenStudy (anonymous):

1/x

OpenStudy (amistre64):

thats right :) but more proper its Dx[ln(x)] = \(\frac{dx}{x}\)

OpenStudy (amistre64):

Dx[ln(x^2+10)] is the same fashion; put the innards to the bottom and their derivative up top Dx(x^2+10) 2x ----------- = -------- (x^2+10) (x^2+10)

OpenStudy (amistre64):

it applying the "chain rule"

OpenStudy (anonymous):

thank you.

OpenStudy (amistre64):

yep :)

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