Question

write an equation of the line through (-4,3) that is perpendicular to the line 2x-y+3=0

Answer 1

so if the slope is 2 then the perpendicular slope is -1/2

Answer 2

2x-y+3=0 ; get rid of the +3 and 0

2x-y=n

now switch x and y coeffs

-x+2y = n ; and change out the operator

-x-2y = n ; fill in your point to calibrate the equation and your done

Answer 3

y-3=-1/2(x+4)

-2y+6=x+4
-2y-x=-2

Answer 4

-x-2y = n ; (-4,3)

-(-4)-2(3) = n

4 -6 = n = -2

-x-2y = -2

-x-2y +2 = 0

Answer 5

same thing yay! thanks amistre

Answer 6

since slope is defined by your x and y coordinates; just flip them and negate one :)

Answer 7

lol okay