write an equation for the line with x-intercept 3 and y-intercept 2/3
y=mx+b
2y/3 =1/3x+b
but how do i find my b?
show all working please
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OpenStudy (anonymous):
y=-2x/9+2/3
OpenStudy (saifoo.khan):
whn x intercepts y = 0
so
2y/3 =1/3x+b
2(0)/3 =1/3(3)+b
0 = 1 +b
b = -1
OpenStudy (saifoo.khan):
now whts that?
OpenStudy (anonymous):
m=-b/x
OpenStudy (anonymous):
no?
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OpenStudy (anonymous):
no thats not how we solve it my apologies
OpenStudy (anonymous):
this is the double intercept so we use the formula x/a+y/b=1
where a is the x-intercept and b is the y-intercept
OpenStudy (anonymous):
x/3+3y/2=1
y=-2x/9+2/3
OpenStudy (anonymous):
thanks still saifoo.khan
OpenStudy (radar):
You are provided with 2 points P1(0,2/3) and P2(2,0)
Use the formula for slope m=(y2-Y1)/(x2-x1)=(0-2/3)/(2-0)=(-2/3)/2=-1/3
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OpenStudy (radar):
Slope is as shown -1/3
Now pick one of the points and use the formula y=mx+b
using the point P1(0,-2/3) plug in those values
-2/3=-1/3(0)+b
b=-2/3
y=-2/3x-2/3