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how do I solve 3x(e^x) + (x^2)(e^x) = 0 ?
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factor out an \[e^x\] and ignore it because it is never 0
just solve \[3x+x^2=0 \]
Since e^x is never 0, we can divide it out to get 3x + x^2 = 0.
i get x= 0 or x =-3
Same here.
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thank you.
yw
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