Question

a ball is dropped from a heiht of 100 feet one second later another ball is dropped from a height of 75 feet .which ball hits the ground first???

Answer 1

equation for first is
\[h(t)=100-16t^2\]

Answer 2

after one second it is 84 feet yes?

Answer 3

and it's velocity is
\[h'(1)=-32\]

Answer 4

so i guess the new equation, starting at t = 1 is
\[h(t)=84-32t-16t^2\]

Answer 5

other one has equation
\[h(t)=75-16t^2\]

Answer 6

see which gets to zero first

Answer 7

if i knew would i ask you???

Answer 8

what i mean is set each equation above = 0 and solve.

Answer 9

whatever is time is least is the first to get there. i.e. solve
\[84-32t-16t^2=0\] and
\[75-16t^2=0\]

Answer 10

first one gives
\[t=\frac{3}{2}\]

Answer 11

second one gives
\[\frac{5\sqrt{3}}{4}\] which is bigger than 1.5

Answer 12

so first ball hits ground first\??

Answer 13

1st ball falls in 4.47s(approx)
2nd in 3.8s.
so if the 2nd ball is thrown 1 second later...
the 1st ball should fall first.