Solve the equations and check your solutions. If there is no solution, say so ( I have the answer which is y=-1 I just to know the step by step please. thanks in advance) 2/3+5/(y-4)=(y+6)/(3y-12)
\[\frac{2}{3}+\frac{5}{(y-4)}=\frac{(y+6)}{(3y-12)}\] rewrite as \[\frac{2}{3}+\frac{5}{(y-4)}=\frac{(y+6)}{3(y-4}\] multiply both side of the equation by \[3(y-4)\] in order to "clear" the fractions
with the result \[2(y-4)+3(5)=y+6\]
multiply and combine like terms with the result \[2y+7=y+6\] then finally isolating y we get \[y= -1\]
no do not do it the hard way. there is no need to solve a quadratic equation here and in any case 4 is not a solution because you cannot replace y by 4 in the original expression
exactly @Toriqur when you combine fractions the way you have, you introduce extra factors into the equation. In this case an extra factor of y-4 the least common denominator for the entire equation is 3(y-4)
ebbflo (nice) has it
satellite73: thanks for chiming in, this thread is more or less dead but its good to have good information none the less. I have witnessed teachers instructing their students to combine fractions in exactly that manner because(i am guessing) it works out fine in the end when adding numerical fractions.
math teachers generally suck. if i see another question asking to "simplify" i am going to chuck a fit
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