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Mathematics 16 Online
OpenStudy (anonymous):

How do I multiply the sqaure roots of two negative numbers?

OpenStudy (anonymous):

Give an example. You would understand better with an example. -1=i

OpenStudy (anonymous):

\[\sqrt{-a} \times \sqrt{-b} = \sqrt{ab}\]

OpenStudy (anonymous):

\[\sqrt{-7}\sqrt{-168}\]

OpenStudy (anonymous):

\[\sqrt{-7} \sqrt{-168} = \sqrt{7 \times 168} = \sqrt{1176} \approx 34.29\]

OpenStudy (anonymous):

Thanks for the help! Are you certain this is correct? and how do you find the square roots of such large numbers?

OpenStudy (anonymous):

Hmm. If you're supposed to leave it in radical form: \[\sqrt{-7}\sqrt{-168} = \sqrt{-7}\sqrt{-7\times24} = 7\sqrt{24} = 14\sqrt{6}\]

OpenStudy (anonymous):

I think you should look again at your answer, hicninja

OpenStudy (anonymous):

I suppose you could factor out "i" from each of the square roots and get the negative of my answer as the answer, but actually both are correct.

OpenStudy (anonymous):

\[\sqrt{-a}\sqrt{-b}=\sqrt{-1a}\sqrt{-1b}=i \sqrt{a} i \sqrt{b}= i ^{2}\sqrt{a} \sqrt{b} =-\sqrt{a} \sqrt{b}\]

OpenStudy (anonymous):

Either is correct. When factoring \[\sqrt{-1}\] out of a negative radical, you get \[\pm i\]. See here: http://mathforum.org/library/drmath/view/53873.html

OpenStudy (anonymous):

-i -i = i^2 = -1

OpenStudy (anonymous):

but you factored out 2 i's. So you have: \[\pm i \times \pm i = \pm 1\]

OpenStudy (anonymous):

because the first i could be positive, and the second negative, or vice-versa.

OpenStudy (anonymous):

You need to be consistent, either factor out 2 negative i's or 2 positive i's ie -1. Anyway, http://www.wolframalpha.com/input/?i=sqrt%28-7%29sqrt%28-168%29

OpenStudy (anonymous):

You don't need to be consistent. However, Google also gives your answer. I maintain either answer is accurate. :-)

OpenStudy (anonymous):

look, just go to http://en.wikipedia.org/wiki/Imaginary_unit and scroll down to the section "proper use" Of course, you can maintain your position if you wish, but it will cost you marks:-)

OpenStudy (anonymous):

OK, you win. At least the last sentence implies the problem should be specified as: \[i\sqrt{a}\times i\sqrt{b}\] so as to avoid this kind of confusion. :-)

OpenStudy (anonymous):

As I was careful to do in my derivation. if you are asking me whether i is a bit flaky sometimes, well I would agree with you. Sometimes the definitions get mixed up with the conventions.

OpenStudy (anonymous):

Come on hickninja, don't give in so easily: fight.

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