How do I multiply the sqaure roots of two negative numbers?
Give an example. You would understand better with an example. -1=i
\[\sqrt{-a} \times \sqrt{-b} = \sqrt{ab}\]
\[\sqrt{-7}\sqrt{-168}\]
\[\sqrt{-7} \sqrt{-168} = \sqrt{7 \times 168} = \sqrt{1176} \approx 34.29\]
Thanks for the help! Are you certain this is correct? and how do you find the square roots of such large numbers?
Hmm. If you're supposed to leave it in radical form: \[\sqrt{-7}\sqrt{-168} = \sqrt{-7}\sqrt{-7\times24} = 7\sqrt{24} = 14\sqrt{6}\]
I think you should look again at your answer, hicninja
I suppose you could factor out "i" from each of the square roots and get the negative of my answer as the answer, but actually both are correct.
\[\sqrt{-a}\sqrt{-b}=\sqrt{-1a}\sqrt{-1b}=i \sqrt{a} i \sqrt{b}= i ^{2}\sqrt{a} \sqrt{b} =-\sqrt{a} \sqrt{b}\]
Either is correct. When factoring \[\sqrt{-1}\] out of a negative radical, you get \[\pm i\]. See here: http://mathforum.org/library/drmath/view/53873.html
-i -i = i^2 = -1
but you factored out 2 i's. So you have: \[\pm i \times \pm i = \pm 1\]
because the first i could be positive, and the second negative, or vice-versa.
You need to be consistent, either factor out 2 negative i's or 2 positive i's ie -1. Anyway, http://www.wolframalpha.com/input/?i=sqrt%28-7%29sqrt%28-168%29
You don't need to be consistent. However, Google also gives your answer. I maintain either answer is accurate. :-)
look, just go to http://en.wikipedia.org/wiki/Imaginary_unit and scroll down to the section "proper use" Of course, you can maintain your position if you wish, but it will cost you marks:-)
OK, you win. At least the last sentence implies the problem should be specified as: \[i\sqrt{a}\times i\sqrt{b}\] so as to avoid this kind of confusion. :-)
As I was careful to do in my derivation. if you are asking me whether i is a bit flaky sometimes, well I would agree with you. Sometimes the definitions get mixed up with the conventions.
Come on hickninja, don't give in so easily: fight.
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